118. Pascal's Triangle

Easy (Dễ) C++ Python 🔗 Xem trên LeetCode

📋 Đề Bài

Given an integer numRows, return the first numRows of Pascal's triangle.

In Pascal's triangle, each number is the sum of the two numbers directly above it as shown:

 

Example 1:

Input: numRows = 5
Output: [[1],[1,1],[1,2,1],[1,3,3,1],[1,4,6,4,1]]

Example 2:

Input: numRows = 1
Output: [[1]]

 

Constraints:

  • 1 <= numRows <= 30

🧠 Thuật Toán & Kỹ Thuật

Bit Manipulation (Thao tác bit)
⏱️ Thời gian O(n²)
💾 Không gian O(n)

💻 Lời Giải

C++ 0118-pascals-triangle.cpp
class Solution {
public:
    vector<vector<int>> generate(int numRows) {
        vector<vector<int>> tri(numRows);
        
        for (int i = 1; i <= numRows; ++i) {
            vector<int> row(i, 1);
            for (int j = 1; j < i - 1; ++j) {
                row[j] = tri[i - 2][j - 1] + tri[i - 2][j];
            }
            tri[i - 1] = row;
        }
        
        return tri;
    }
};
Python 0118-pascals-triangle.py
class Solution:
    def generate(self, numRows: int) -> List[List[int]]:
        ans = []
        for i in range(numRows):
            tmp = [1] * (i + 1)
            for j in range(1, i):
                tmp[j] = ans[i - 1][j - 1] + ans[i - 1][j]
            ans.append(tmp)
        return ans