377. Combination Sum IV

Medium (Trung bình) C++ 🔗 Xem trên LeetCode

📋 Đề Bài

Given an array of distinct integers nums and a target integer target, return the number of possible combinations that add up to target.

The test cases are generated so that the answer can fit in a 32-bit integer.

 

Example 1:

Input: nums = [1,2,3], target = 4
Output: 7
Explanation:
The possible combination ways are:
(1, 1, 1, 1)
(1, 1, 2)
(1, 2, 1)
(1, 3)
(2, 1, 1)
(2, 2)
(3, 1)
Note that different sequences are counted as different combinations.

Example 2:

Input: nums = [9], target = 3
Output: 0

 

Constraints:

  • 1 <= nums.length <= 200
  • 1 <= nums[i] <= 1000
  • All the elements of nums are unique.
  • 1 <= target <= 1000

 

Follow up: What if negative numbers are allowed in the given array? How does it change the problem? What limitation we need to add to the question to allow negative numbers?

🧠 Thuật Toán & Kỹ Thuật

Dynamic Programming (Quy hoạch động)
⏱️ Thời gian O(n²)
💾 Không gian O(n)

💻 Lời Giải

C++ 0377-combination-sum-iv.cpp
class Solution {
public:
    int combinationSum4(vector<int>& nums, int target) {
        vector<uint> dp(target + 1);
        dp[0] = 1;
        for (int i = 1; i <= target; ++i) {
            for (int num : nums) {
                if (i - num >= 0) {
                    dp[i] += dp[i - num];
                }
            }
        }
        return dp[target];
    }
};