404. Sum of Left Leaves

Easy (Dễ) Python 🔗 Xem trên LeetCode

📋 Đề Bài

Given the root of a binary tree, return the sum of all left leaves.

A leaf is a node with no children. A left leaf is a leaf that is the left child of another node.

 

Example 1:

Input: root = [3,9,20,null,null,15,7]
Output: 24
Explanation: There are two left leaves in the binary tree, with values 9 and 15 respectively.

Example 2:

Input: root = [1]
Output: 0

 

Constraints:

  • The number of nodes in the tree is in the range [1, 1000].
  • -1000 <= Node.val <= 1000

🧠 Thuật Toán & Kỹ Thuật

DFS (Tìm kiếm theo chiều sâu)Tree Traversal (Duyệt cây)
⏱️ Thời gian O(V+E)
💾 Không gian O(V)

💻 Lời Giải

Python 0404-sum-of-left-leaves.py
# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, val=0, left=None, right=None):
#         self.val = val
#         self.left = left
#         self.right = right

class Solution:
    def sumOfLeftLeaves(self, root: Optional[TreeNode]) -> int:
        self.ans = 0
        
        def dfs(root, isLeft = False):
            if not root:
                return
            
            if isLeft and not root.left and not root.right:
                self.ans += root.val
                
            dfs(root.left, True)
            dfs(root.right, False)
                
        dfs(root)
        
        return self.ans