677. Map Sum Pairs
Đề Bài
Design a map that allows you to do the following:
- Maps a string key to a given value.
- Returns the sum of the values that have a key with a prefix equal to a given string.
Implement the MapSum class:
MapSum()Initializes theMapSumobject.void insert(String key, int val)Inserts thekey-valpair into the map. If thekeyalready existed, the originalkey-valuepair will be overridden to the new one.int sum(string prefix)Returns the sum of all the pairs' value whosekeystarts with theprefix.
Example 1:
Input
["MapSum", "insert", "sum", "insert", "sum"]
[[], ["apple", 3], ["ap"], ["app", 2], ["ap"]]
Output
[null, null, 3, null, 5]
Explanation
MapSum mapSum = new MapSum();
mapSum.insert("apple", 3);
mapSum.sum("ap"); // return 3 (apple = 3)
mapSum.insert("app", 2);
mapSum.sum("ap"); // return 5 (apple + app = 3 + 2 = 5)
Constraints:
1 <= key.length, prefix.length <= 50keyandprefixconsist of only lowercase English letters.1 <= val <= 1000- At most
50calls will be made toinsertandsum.
Thuật Toán & Kỹ Thuật
⏱️ Thời gian
O(n²)
💾 Không gian
O(n)
Lời Giải
Python
0677-map-sum-pairs.py
class Node:
def __init__(self):
self.total = 0
self.children = defaultdict(Node)
class Trie:
def __init__(self):
self.root = Node()
def insert(self, word: str, diff: int) -> None:
root = self.root
for char in word:
root = root.children[char]
root.total += diff
def find(self, prefix: str) -> int:
root = self.root
for char in prefix:
if char not in root.children:
return 0
root = root.children[char]
return root.total
class MapSum:
def __init__(self):
self.trie = Trie()
self.umap = defaultdict(int)
def insert(self, key: str, val: int) -> None:
diff = val - self.umap[key]
self.trie.insert(key, diff)
self.umap[key] = val
def sum(self, prefix: str) -> int:
return self.trie.find(prefix)
# Your MapSum object will be instantiated and called as such:
# obj = MapSum()
# obj.insert(key,val)
# param_2 = obj.sum(prefix)