40. Combination Sum II

Medium (Trung bình) Python 🔗 Xem trên LeetCode

📋 Đề Bài

Given a collection of candidate numbers (candidates) and a target number (target), find all unique combinations in candidates where the candidate numbers sum to target.

Each number in candidates may only be used once in the combination.

Note: The solution set must not contain duplicate combinations.

 

Example 1:

Input: candidates = [10,1,2,7,6,1,5], target = 8
Output: 
[
[1,1,6],
[1,2,5],
[1,7],
[2,6]
]

Example 2:

Input: candidates = [2,5,2,1,2], target = 5
Output: 
[
[1,2,2],
[5]
]

 

Constraints:

  • 1 <= candidates.length <= 100
  • 1 <= candidates[i] <= 50
  • 1 <= target <= 30

🧠 Thuật Toán & Kỹ Thuật

DFS (Tìm kiếm theo chiều sâu)Sorting (Sắp xếp)
⏱️ Thời gian O(n log n)
💾 Không gian O(n)

💻 Lời Giải

Python 0040-combination-sum-ii.py
class Solution:
    def combinationSum2(self, candidates: List[int], target: int) -> List[List[int]]:
        candidates.sort()
        n = len(candidates)
        ans = set()
        sumCandi = sum(candidates)
        
        def dfs(i, s, path):
            if s == target:
                ans.add(tuple(path))
                return
            if i == n or s > target:
                return
            for j in range(i, n):
                if j > i and candidates[j - 1] == candidates[j]:
                    continue
                dfs(j + 1, s + candidates[j], path + [candidates[j]])
                
        dfs(0, 0, [])
        
        return ans