41. First Missing Positive
Đề Bài
Given an unsorted integer array nums, return the smallest missing positive integer.
You must implement an algorithm that runs in O(n) time and uses constant extra space.
Example 1:
Input: nums = [1,2,0] Output: 3 Explanation: The numbers in the range [1,2] are all in the array.
Example 2:
Input: nums = [3,4,-1,1] Output: 2 Explanation: 1 is in the array but 2 is missing.
Example 3:
Input: nums = [7,8,9,11,12] Output: 1 Explanation: The smallest positive integer 1 is missing.
Constraints:
1 <= nums.length <= 105-231 <= nums[i] <= 231 - 1
Thuật Toán & Kỹ Thuật
⏱️ Thời gian
O(n log n)
💾 Không gian
O(n)
Lời Giải
Python
0041-first-missing-positive.py
class Solution:
def firstMissingPositive(self, nums: List[int]) -> int:
nums = list(set(nums))
step = 1
nums.sort()
for num in nums:
if num <= 0:
continue
if num != step:
return step
step += 1
return step